Missing C# feature ? - Totally hiding derived members
So here's my problem. I have class Foo:
public class Foo{
public void DoStuff()
{
...
}
}
and i have class Bar derived from it. I want class Bar to Hide the "DoStuff" and expose it's own implementation of "DoStuff()". Simple, right?
public class Bar:Foo
{
//Hide the default memebr
new private void DoStuff(){
}
public void DoStuff(int argument){}
}
Ok. Done. But watch this: writing the following line in VS.NET:
Bar b = new Bar();
b. ///->>>>You get both the Bar.DoStuff AND the Foo.DoStuff in the Tooltips.
meaning : you cannot hide inharited members totally. you must implement them to hide the default functionality. I looked it up on MSDN and found this article which states so clearly:
"A declaration of a new member hides an inherited member only within the scope of the new member.
class Base { public static void F() {} } class Derived: Base { new private static void F() {} // Hides Base.F in Derived only } class MoreDerived: Derived { static void G() { F(); } // Invokes Base.F }
In the example above, the declaration of F
in Derived
hides the F
that was inherited from Base
, but since the new F
in Derived
has private access, its scope does not extend to MoreDerived
. Thus, the call F()
in MoreDerived.G
is valid and will invoke Base.F
."
How is that not possible? you'd think it's a pretty legitimate programming way, wouldn;t you? I can;t think of any situation where having this as a possibility is a bad thing...